Challenge 1 - Substitution Cipher


The following ciphertext has been encrypted using a substitution cipher. The encryption key of a substitution cipher is a random permutation of the plaintext's alphabet(in this case: the 26 letters of the latin alphabet). Encryption is done by substituting every character of the plaintext with the corresponding character from the key. The plaintext is, apart from the random flag, written in english language.

Your Ciphertext:

BC OETLWRQESLGT S VAPVWBWAWBRC OBLGZE BV S FZWGRX RM ZCOETLWBCQ PT IGBOG ACBWV RM LDSBCWZNW SEZ EZLDSOZX IBWG OBLGZEWZNW SOOREXBCQ WR S MBNZX VTVWZF WGZ ACBWV FST PZ VBCQDZ DZWWZEV WGZ FRVW ORFFRC LSBEV RM DZWWZEV WEBLDZWV RM DZWWZEV FBNWAEZV RM WGZ SPRKZ SCX VR MREWG WGZ EZOZBKZE XZOBLGZEV WGZ WZNW PT LZEMREFBCQ WGZ BCKZEVZ VAPVWBWAWBRC VAPVWBWAWBRC OBLGZEV OSC PZ ORFLSEZX IBWG WESCVLRVBWBRC OBLGZEV BC S WESCVLRVBWBRC OBLGZE WGZ ACBWV RM WGZ LDSBCWZNW SEZ EZSEESCQZX BC S XBMMZEZCW SCX AVASDDT HABWZ ORFLDZN REXZE PAW WGZ ACBWV WGZFVZDKZV SEZ DZMW ACOGSCQZX PT ORCWESVW BC S VAPVWBWAWBRC OBLGZE WGZ ACBWV RM WGZ LDSBCWZNW SEZ EZWSBCZX BC WGZ VSFZ VZHAZCOZ BC WGZ OBLGZEWZNW PAW WGZ ACBWV WGZFVZDKZV SEZ SDWZEZX WGZEZ SEZ S CAFPZE RM XBMMZEZCW WTLZV RM VAPVWBWAWBRC OBLGZE BM WGZ OBLGZE RLZESWZV RC VBCQDZ DZWWZEV BW BV WZEFZX S VBFLDZ VAPVWBWAWBRC OBLGZE S OBLGZE WGSW RLZESWZV RC DSEQZE QERALV RM DZWWZEV BV WZEFZX LRDTQESLGBO S FRCRSDLGSPZWBO OBLGZE AVZV MBNZX VAPVWBWAWBRC RKZE WGZ ZCWBEZ FZVVSQZ IGZEZSV S LRDTSDLGSPZWBO OBLGZE AVZV S CAFPZE RM VAPVWBWAWBRCV SW XBMMZEZCW LRVBWBRCV BC WGZ FZVVSQZ IGZEZ S ACBW MERF WGZ LDSBCWZNW BV FSLLZX WR RCZ RM VZKZESD LRVVBPBDBWBZV BC WGZ OBLGZEWZNW SCX KBOZ KZEVS LST VLZOBSD SWWZCWBRC WR WGZ YZT BW BV CRW SDISTV LRVVBPDZ WR XZEBKZ S ORFLDZWZ FSLLBCQ RM OGSESOWZEV BM WGZ LDSBCWZNW XRZV CRW ORCWSBC SDD OGSESOWZEV RM WGZ SDLGSPZW WGZ SPRKZ HARWZ MERF IBYBLZXBS XRZV CRW ORCWSBC WGZ DZWWZEV JYU MRE ZNSFLDZ SXXBWBRCSDDT GZEZ BV TRAE MDSQ WR VAPFBW MAJUSZFCCUSLCWBUBLVSHHDMMEKFNJLK

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