The following ciphertext has been encrypted using a substitution cipher. The encryption key of a substitution cipher is a random permutation of the plaintext's alphabet(in this case: the 26 letters of the latin alphabet). Encryption is done by substituting every character of the plaintext with the corresponding character from the key. The plaintext is, apart from the random flag, written in english language.
BM OVWNTHUVZNPW Z KDCKTBTDTBHM OBNPJV BK Z QJTPHF HG JMOVWNTBMU CW XPBOP DMBTK HG NRZBMTJLT ZVJ VJNRZOJF XBTP OBNPJVTJLT ZOOHVFBMU TH Z GBLJF KWKTJQ TPJ DMBTK QZW CJ KBMURJ RJTTJVK TPJ QHKT OHQQHM NZBVK HG RJTTJVK TVBNRJTK HG RJTTJVK QBLTDVJK HG TPJ ZCHAJ ZMF KH GHVTP TPJ VJOJBAJV FJOBNPJVK TPJ TJLT CW NJVGHVQBMU TPJ BMAJVKJ KDCKTBTDTBHM KDCKTBTDTBHM OBNPJVK OZM CJ OHQNZVJF XBTP TVZMKNHKBTBHM OBNPJVK BM Z TVZMKNHKBTBHM OBNPJV TPJ DMBTK HG TPJ NRZBMTJLT ZVJ VJZVVZMUJF BM Z FBGGJVJMT ZMF DKDZRRW YDBTJ OHQNRJL HVFJV CDT TPJ DMBTK TPJQKJRAJK ZVJ RJGT DMOPZMUJF CW OHMTVZKT BM Z KDCKTBTDTBHM OBNPJV TPJ DMBTK HG TPJ NRZBMTJLT ZVJ VJTZBMJF BM TPJ KZQJ KJYDJMOJ BM TPJ OBNPJVTJLT CDT TPJ DMBTK TPJQKJRAJK ZVJ ZRTJVJF TPJVJ ZVJ Z MDQCJV HG FBGGJVJMT TWNJK HG KDCKTBTDTBHM OBNPJV BG TPJ OBNPJV HNJVZTJK HM KBMURJ RJTTJVK BT BK TJVQJF Z KBQNRJ KDCKTBTDTBHM OBNPJV Z OBNPJV TPZT HNJVZTJK HM RZVUJV UVHDNK HG RJTTJVK BK TJVQJF NHRWUVZNPBO Z QHMHZRNPZCJTBO OBNPJV DKJK GBLJF KDCKTBTDTBHM HAJV TPJ JMTBVJ QJKKZUJ XPJVJZK Z NHRWZRNPZCJTBO OBNPJV DKJK Z MDQCJV HG KDCKTBTDTBHMK ZT FBGGJVJMT NHKBTBHMK BM TPJ QJKKZUJ XPJVJ Z DMBT GVHQ TPJ NRZBMTJLT BK QZNNJF TH HMJ HG KJAJVZR NHKKBCBRBTBJK BM TPJ OBNPJVTJLT ZMF ABOJ AJVKZ NZW KNJOBZR ZTTJMTBHM TH TPJ SJW BT BK MHT ZRXZWK NHKKBCRJ TH FJVBAJ Z OHQNRJTJ QZNNBMU HG OPZVZOTJVK BG TPJ NRZBMTJLT FHJK MHT OHMTZBM ZRR OPZVZOTJVK HG TPJ ZRNPZCJT TPJ ZCHAJ YDHTJ GVHQ XBSBNJFBZ FHJK MHT OHMTZBM TPJ RJTTJVK ESI GHV JLZQNRJ ZFFBTBHMZRRW PJVJ BK WHDV GRZU TH KDCQBT ASCJTUDMFXLMRBZBGBMVFRLEHGYNHNYT
Submit Solution Help